Showing (AB)C=A(BC) is relatively a simple matter using the super duper summation convention.
Firstly the ith row, jth column of a matrix A is designated by Aij, Aij or Aij.
Matrix multiplication is then defined as
[XY]ij=XikYkj
where square brackets have been placed around XY to designate the ij element of the matrix X⋅Y.
[(AB)C]ij=(AB)ikCkj=AilBlkCkj=Ail(BlkCkj)=Ail[BC]lj=[A(BC)]ij∴(AB)C=A(BC)
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